Exams › SSC CGL (Prelims) › General

If $3 \# 4 = 25$ and $5 \# 2 = 29$, then $7 \# 6 = ?$

1. 82
2. 88
3. 85
4. 86

Correct answer: 85

Solution

For $3 \# 4$, $3\times4+3+4=12+7=19$, so that does not fit. But $3^2+4^2=25$ and $5^2+2^2=29$, so the operation is the sum of squares. Thus, $7 \# 6=7^2+6^2=49+36=85$.

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