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A circle is inscribed in a right-angled triangle whose perpendicular sides are 9 cm and 12 cm. Find the radius of the inscribed circle.

1. 2 cm
2. 3 cm
3. 4 cm
4. 5 cm

Correct answer: 3 cm

Solution

The hypotenuse is $\sqrt{9^2+12^2}=15$ cm. For a right triangle, the inradius is $r=(9+12-15)/2=3$ cm.

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