Exams › SSC CGL (Prelims) › General

A tank holds a mixture of strawberry, blueberry, and raspberry juices in the ratio 6:9:5 respectively. 40 litres of this mixture is taken out, and then 15 litres of strawberry juice and 10 litres of raspberry juice are added to the tank. If the resultant quantity of blueberry juice is 22 litres more than the resultant quantity of strawberry juice, what was the initial quantity of mixture in the tank (approximately, in litres)?

1. 287
2. 300
3. 320
4. 340

Correct answer: 287

Solution

Let the initial mixture be \(x\) litres. Then strawberry, blueberry, and raspberry quantities are \(\frac{6x}{20}, \frac{9x}{20}, \frac{5x}{20}\). After removing 40 litres, the remaining amounts are reduced proportionally, and then 15 litres of strawberry and 10 litres of raspberry are added. Using the condition that blueberry exceeds strawberry by 22 litres gives \(\frac{9x}{20}-18 = \left(\frac{6x}{20}-12\right)+15+22\), which yields \(x\approx 286.67\), so the initial quantity is about 287 litres.

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