There are 6 consecutive even numbers M₁, M₂, M₃, M₄, M₅, M₆ and 5 consecutive odd numbers N₁, N₂, N₃, N₄, N₅. The average of the even numbers is 4 more than the average of the odd numbers. If the sum of the even numbers is 24 more than the sum of the odd numbers, find the average of the od

Question

There are 6 consecutive even numbers M₁, M₂, M₃, M₄, M₅, M₆ and 5 consecutive odd numbers N₁, N₂, N₃, N₄, N₅. The average of the even numbers is 4 more than the average of the odd numbers. If the sum of the even numbers is 24 more than the sum of the odd numbers, find the average of the odd numbers.

Accepted Answer

0. For 6 even numbers, sum = 6 × (even average), and for 5 odd numbers, sum = 5 × (odd average). Let odd average be x, so even average is x + 4. Given 6(x + 4) = 5x + 24, which gives x = 0.

Solution

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