Exams › SSC CGL (Prelims) › General
A tank contains liquids A, B, and C in the ratio $8:6:4$. 30 liters of the mixture are drained out, after which 12 liters of A and 8 liters of C are added. In the final mixture, the quantity of A is 20 liters more than the quantity of B. Find the initial total volume of the mixture in the tank.
- 106 L
- 172 L
- 102 L
- 190 L
Correct answer: 102 L
Solution
Let the initial total volume be $V$. Then initial amounts are $A=\frac{8}{18}V$, $B=\frac{6}{18}V$, $C=\frac{4}{18}V$. After removing 30 L, the remaining amounts are reduced proportionally; then 12 L of A and 8 L of C are added. Using the condition that final A is 20 L more than final B gives $V=102$ L.
Related SSC CGL (Prelims) General questions
⚔️ Practice SSC CGL (Prelims) General free + battle 1v1 →