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A solution has acid and water in the ratio $6:4$. If 5 L of water are added, the new ratio becomes $6:5$. What was the original quantity of acid?
- 15 L
- 18 L
- 24 L
- 30 L
Correct answer: 30 L
Solution
Let the original acid and water be $6x$ and $4x$. After adding 5 L water, the ratio becomes $6:5$, so $\frac{6x}{4x+5}=\frac{6}{5}$. Solving gives $30x=24x+30$, hence $x=5$ and acid $=6x=30$ L.
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