Exams › SSC CGL (Prelims) › General

If $4 \# 3 = 19$ and $6 \# 5 = 41$, then $8 \# 7 = ?$

1. 63
2. 65
3. 71
4. 73

Correct answer: 71

Solution

The pattern is $a \# b = ab + a + b$. For $4 \# 3$, we get $12+4+3=19$ and for $6 \# 5$, we get $30+6+5=41$. So $8 \# 7 = 56+8+7 = 71$.

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