A cricketer's average score over a series of matches is 42. If she scores 138 runs in the next match, her average increases to 46. How many matches had she played before this?

Question

Accepted Answer

23. If the average before the next match is 42 over $n$ matches, total runs are $42n$. After scoring 138, the average becomes 46 over $n+1$ matches, so $42n+138=46(n+1)$. Solving gives $n=23$.

A cricketer's average score over a series of matches is 42. If she scores 138 runs in the next match, her average increases to 46. How many matches had she played before this?

Solution

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