StreakPeaked· Practice

ExamsSSC CGL (Prelims)General

The second letter-group is derived from the first by a fixed alphabetical shift. Apply the same rule to the third group: QDXM : SFYN :: UIOZ : ?

  1. PAQM
  2. LPWA
  3. QNLA
  4. WKPA

Correct answer: WKPA

Solution

From QDXM to SFYN the shifts are Q->S (+2), D->F (+2), X->Y (+1), M->N (+1). Applying +2,+2,+1,+1 to UIOZ gives U->W, I->K, O->P, Z->A = WKPA.

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