SSC CGL (Prelims) General: Data Interpretation questions with solutions

Q1. Table: Daily production (in units) of 5 machines over 4 days. Day 1: M1 150, M2 140, M3 180, M4 130, M5 160; Day 2: M1 160, M2 135, M3 190, M4 135, M5 165; Day 3: M1 155, M2 145, M3 185, M4 140, M5 170; Day 4: M1 165, M2 150, M3 195, M4 145, M5 175. What is the average daily production of Machine M3?

1. 187.5
2. 185
3. 190
4. 182.5

Answer: 187.5

The production of M3 over 4 days is 180, 190, 185, and 195. Their sum is 750, and dividing by 4 gives 187.5.

Q2. The number of workers in two departments X and Y with different experience levels is shown in the table: Experience level | Dept X | Dept Y < 5 years | 8 | 6 5–10 years | 12 | 10 > 10 years | 5 | 4 What is the ratio of workers with less than 10 years' experience in Dept X to Dept Y?

1. 2:1
2. 20:6
3. 4:3
4. 5:4

Answer: 5:4

Workers with less than 10 years' experience are those in the '< 5 years' and '5–10 years' groups. So Dept X has $8+12=20$ and Dept Y has $6+10=16$, giving the ratio $20:16 = 5:4$.

Q3. Table: Sales of 3 items over 3 months Item | Jan | Feb | Mar X | 150 | 180 | 170 Y | 120 | 110 | 130 Z | 200 | 210 | 190 Which item had the highest average sales?

1. X
2. Y
3. Z
4. X and Z equal

Answer: Z

For X, average = \((150+180+170)/3=500/3\). For Y, average = \((120+110+130)/3=360/3=120\). For Z, average = \((200+210+190)/3=600/3=200\), which is the highest.

Q4. Table: Quarterly Revenue. Item Q1 Q2 Q3 Q4 Product A 45 55 50 60 Product B 70 72 68 75. What is the average quarterly revenue of Product B?

1. Rs. 71.25 lakhs
2. Rs. 71.5 lakhs
3. Rs. 72 lakhs
4. Rs. 72.5 lakhs

Answer: Rs. 71.25 lakhs

For Product B, the quarterly revenues are 70, 72, 68, and 75. Their sum is 285, and 285 ÷ 4 = 71.25 lakhs.

Q5. Table - Weekly Electricity Usage (kWh) Apartment | Mon | Tue | Wed | Thu | Fri Flat 1 | 12 | 14 | 13 | 15 | 16 Flat 2 | 18 | 17 | 19 | 16 | 18 What is the overall average daily electricity usage for both flats?

1. 16 kWh
2. 15.8 kWh
3. 17 kWh
4. 14.5 kWh

Answer: 15.8 kWh

Sum of Flat 1 usage = 12+14+13+15+16 = 70. Sum of Flat 2 usage = 18+17+19+16+18 = 88. Total = 158, and the average over 10 days/entries is 158/10 = 15.8 kWh.

Q6. The number of students in two sections A and B having different heights is shown in the table below: Height (in metres) | Section A | Section B 1.55 | 6 | 5 1.60 | 10 | 0 1.62 | 14 | 15 1.65 | 16 | 11 1.68 | 9 | 8 1.71 | 7 | 6 1.75 | 5 | 4 What is the ratio of the number of students with a height of 1.62 metres in Section A to the total number of students in Section A?

1. 14:67
2. 14:62
3. 1:4
4. 7:33

Answer: 14:67

The number of students in Section A is 6 + 10 + 14 + 16 + 9 + 7 + 5 = 67. The number of students with height 1.62 m in Section A is 14. So the required ratio is 14:67.

Q7. From a sample of 250 data scientists, determine the ratio of those proficient in Python to those proficient in R. Category | Number of Data Scientists ---|--- Proficient in Python and R | 50 Proficient in Python only | 80 Proficient in R only | 70 Proficient in neither language | 50 Total sample size | 250

1. 13:12
2. 12:13
3. 8:7
4. 7:8

Answer: 13:12

Python-proficient students = Python only + both = 80 + 50 = 130. R-proficient students = R only + both = 70 + 50 = 120. Therefore, the ratio of Python to R is 130:120 = 13:12.

Q8. The table shows the daily output (in units) of five machines over four days: Day 1: M1 = 150, M2 = 140, M3 = 180, M4 = 130, M5 = 160; Day 2: M1 = 160, M2 = 135, M3 = 190, M4 = 135, M5 = 165; Day 3: M1 = 155, M2 = 145, M3 = 185, M4 = 140, M5 = 170; Day 4: M1 = 165, M2 = 150, M3 = 195, M4 = 145, M5 = 175. Find the average daily production of Machine M3.

1. 187.5
2. 185
3. 190
4. 182.5

Answer: 187.5

The average daily production is the total output over 4 days divided by 4. For M3, the outputs are 180, 190, 185, and 195, whose sum is 750. So the average is 750/4 = 187.5 units.