Exams › SSC CGL (Prelims) › General › Arithmetic Operations
38 questions with worked solutions.
Answer: 3
Replace the symbols: 15 ÷ 3 + 2 - 4. Now evaluate using order of operations: 15 ÷ 3 = 5, then 5 + 2 - 4 = 3. So the correct value is 3.
Q2. If '+' means '−', '−' means '+', and '×' means '÷', then 50 + 10 − 5 × 5 = ?
Answer: 41
Using the given meanings, the expression becomes 50 − 10 + 5 ÷ 5. Applying BODMAS gives 50 − 10 + 1 = 41.
Q3. If ‘+’ means × and ‘@’ means +, then 8 @ 3 + 4 = ?
Answer: 28
Given ‘+’ means multiplication and ‘@’ means addition, the expression becomes 8 + 3 × 4. By BODMAS, 3 × 4 = 12, then 8 + 12 = 28.
Q4. If the sum of 48 and 32 is multiplied by 6, the result is:
Answer: 480
Add the two numbers first: 48 + 32 = 80. Then multiply by 6: 80 × 6 = 480.
Q5. If the sum of 42 and 42 is multiplied by 4, what is the result?
Answer: 336
The sum of 42 and 42 is 84. Multiplying 84 by 4 gives 336, so that is the correct result.
Q6. If 6 # 3 = 18 and 8 # 4 = 32, then 10 # 5 = ?
Answer: 50
In both examples, the result is the product of the two numbers: 6×3=18 and 8×4=32. Therefore, 10#5 = 10×5 = 50.
Answer: 3
Replacing the signs gives 8 − 4 × 12 ÷ 6 + 3. Now evaluate multiplication and division from left to right: 4 × 12 = 48, 48 ÷ 6 = 8, so the expression becomes 8 − 8 + 3 = 3.
Q8. If '#' means '+', '@' means '−', and the third symbol means '×', find the value of: 8 3 @ 4 # 2
Answer: 22
Using the given meanings, the expression is 8 3 − 4 + 2, which is intended as 8 × 3 − 4 + 2. Applying BODMAS gives 24 − 4 + 2 = 22.
Q9. Evaluate: $(6 + 4) \times (8 - 3)$
Answer: 50
First evaluate the brackets: 6 + 4 = 10 and 8 − 3 = 5. Then multiply: 10 × 5 = 50.
Q10. If A = +, B = -, C = ×, and D = ÷, find the value of: 20 B 5 C 2 A 10 D 5
Answer: 12
Substitute the symbols: 20 - 5 × 2 + 10 ÷ 5. Now evaluate × and ÷ first: 5 × 2 = 10 and 10 ÷ 5 = 2. So the expression becomes 20 - 10 + 2 = 12.
Q11. If the sum of 18 and 32 is multiplied by 4, what is the result?
Answer: 200
First, add 18 and 32 to get 50. Then multiply 50 by 4 to obtain 200.
Answer: ₹ 118
Cost of 4 pens = \(4 \times 12 = 48\). Cost of 2 notebooks = \(2 \times 35 = 70\). Total cost = \(48 + 70 = 118\).
Q13. If ‘A’ means ‘×’, ‘B’ means ‘÷’, ‘C’ means ‘+’, and ‘D’ means ‘−’, find the value of: 20 B 5 C 6 A 2
Answer: 16
Replacing the symbols gives 20 ÷ 5 + 6 × 2. Using BODMAS, 20 ÷ 5 = 4 and 6 × 2 = 12, then 4 + 12 = 16. So the value is 16.
Answer: 7 @ 2 = 21
In the first three options, the result equals the product of the two numbers: 8 × 2 = 16, 6 × 3 = 18, and 5 × 4 = 20. But 7 × 2 = 14, not 21. So this is the odd one out.
Q15. If ‘L’ = +, ‘M’ = -, ‘N’ = ×, and ‘O’ = ÷, which equation is incorrect?
Answer: 20 M 4 O 2 N 3 = 24
Substitute the symbols: M = -, O = ÷, N = ×. Then evaluate the expression using BODMAS/PEMDAS. The given equation does not satisfy the equality after correct calculation, so it is the incorrect one.
Answer: 8
After substitution, the expression becomes \((40 ÷ 5 + 6 × 2) - (18 ÷ 3 × 2)\). Using BODMAS, the first bracket is 8 + 12 = 20 and the second bracket is 6 × 2 = 12. Therefore, 20 − 12 = 8.
Answer: Only I
After interchanging + and -, equation I becomes 16 ÷ 4 - 6 × 2 + 5 = 4 - 12 + 5 = -3, so it is incorrect. Equation II becomes 9 - 8 × 3 ÷ 4 + 2 = 9 - 6 + 2 = 5, which is correct.
Q18. If 6 @ 4 = 28 and 9 @ 2 = 22, then 7 @ 3 = ?
Answer: 25
The pattern is a @ b = a × b + a + b. For 6 @ 4, 6×4+6+4 = 24+10 = 34, so that does not fit; instead the consistent rule is a @ b = a × b + a - b. Using this, 6×4+6-4 = 26, still not matching. The intended pattern is a × b + (a - b) with a small OCR-style inconsistency in the examples; applying the standard SSC pattern gives 7×3 + 7 + 3 = 31, but among the options the expected answer is 25, which corresponds to 7×3 + 4. Since the provided answer key is 25, the question appears to rely on a hidden pattern not fully recoverable from the text.
Q19. Replace the special characters with mathematical signs to make the equation correct: 20 5 # 2 = 10.
Answer: -, ×
Replacing the symbols with - and × gives 20 - 5 × 2 = 20 - 10 = 10, which is correct. The other combinations do not satisfy the equation.
Q20. Which two signs should be swapped to make the equation correct? 24 ÷ 6 + 4 × 3 - 2 = 2
Answer: × and -
Swapping × and - gives 24 ÷ 6 + 4 - 3 × 2. Now, 24 ÷ 6 = 4 and 3 × 2 = 6, so the expression becomes 4 + 4 - 6 = 2. Hence the correct swap is × and -.
Q21. If + = ×, × = -, - = ÷, ÷ = +, then 12 + 4 × 24 - 8 ÷ 4 = ?
Answer: 49
Substituting the symbols gives 12 × 4 - 24 ÷ 8 + 4. Now apply BODMAS: 12 × 4 = 48 and 24 ÷ 8 = 3, so the expression becomes 48 - 3 + 4 = 49.
Q22. If the difference between 48 and 18 is multiplied by 3, what is the result?
Answer: 90
The difference between 48 and 18 is 30. Multiplying 30 by 3 gives 90.
Q23. Choose the correct signs to swap to make the equation correct: 36 ÷ 6 + 8 - 4 × 3 = 35
Answer: - and ×
Swapping '-' and '×' changes the expression to 36 ÷ 6 + 8 × 4 - 3 = 35. Evaluating gives 6 + 32 - 3 = 35, so this is correct.
Answer: 8
Replace the symbols: × → -, ÷ → +, + → ÷, and - → ×. So the expression becomes 8 - 4 + 2 × 6 ÷ 3. Using BODMAS, 2 × 6 ÷ 3 = 4, then 8 - 4 + 4 = 8.
Q25. If ‘×’ = ‘÷’, ‘÷’ = ‘+’, ‘+’ = ‘-’, and ‘-’ = ‘×’, which equation is correct?
Answer: 12 ÷ 4 + 2 × 2 = 15
Using the given replacements, × becomes ÷, ÷ becomes +, + becomes -, and - becomes ×. In option D, 12 ÷ 4 + 2 × 2 becomes 12 + 4 - 2 ÷ 2, which evaluates to 15 after applying the intended substitutions and order of operations. Therefore, option D is correct.
Answer: 34
Replace the symbols as given: 18 ÷ 3 × 6 + 2 - 4. Now apply BODMAS from left to right for multiplication/division: 18 ÷ 3 = 6, 6 × 6 = 36, then 36 + 2 - 4 = 34. So the correct answer is 34.
Q27. If ‘+’ means ‘÷’, ‘-’ means ‘×’ and ‘×’ means ‘-’, then find: 9 + 3 - 2 × 1 = ?
Answer: 5
Using the given meanings, 9 + 3 - 2 × 1 becomes 9 ÷ 3 × 2 - 1. Now evaluate left to right: 9 ÷ 3 = 3, 3 × 2 = 6, and 6 - 1 = 5. Hence, the answer is 5.
Answer: 0
Using the given meanings, the expression becomes 80 ÷ 10 + 4 - 2 × 6. Evaluating it gives 8 + 4 - 12 = 0.
Answer: 4
After replacing the signs, the expression becomes 20 + 4 ÷ 2 - 6 × 3. Using standard order of operations gives 20 + 2 - 18 = 4.
Q30. If ‘+’ means ‘×’, ‘-’ means ‘+’, and ‘×’ means ‘-’, find the value: 12 + 3 - 2 × 1 = ?
Answer: 37
Replacing the signs gives 12 × 3 + 2 - 1. Now evaluate using BODMAS: 12 × 3 = 36, then 36 + 2 - 1 = 37.
Q31. Find the signs to be interchanged so that 24 ÷ 6 + 5 - 4 × 3 = 21.
Answer: - and ×
If - and × are interchanged, the expression becomes 24 ÷ 6 + 5 × 4 - 3 = 21. Evaluating it gives 4 + 20 - 3 = 21, so this is correct.
Answer: + , ×
Using + and × gives 8 + 4 × 2 = 8 + 8 = 16. This makes the equation correct.
Answer: 6 × 4 + 2 ÷ 2 = 14
After replacing the symbols, only one equation fails to satisfy the stated equality. The incorrect one is the option whose transformed expression does not evaluate to the given result.
Answer: Both I and II
Interchanging × and ÷ changes the structure of both equations, and neither of the transformed equations matches the given result. Therefore, both statements become incorrect.
Q35. What should come at the place of the question mark? 3 × 4 + 5 = ?
Answer: 17
By BODMAS, multiplication is done before addition. So 3 × 4 = 12, and 12 + 5 = 17. Hence, 17 is correct.
Q36. If @ = +, # = -, = = ×, and & = ÷, then 8 @ 4 # 2 = ?
Answer: 10
Using the given substitutions, 8 @ 4 # 2 becomes 8 + 4 - 2. Evaluating gives 12 - 2 = 10. So the correct answer is 10.
Answer: + and ×
Substitute the signs and check the expression using BODMAS. With + and ×, we get \(18 + 6 \times 3 = 18 + 18 = 36\), which is correct. The other combinations do not give 36.
Q38. If @ = ×, # = -, = ÷ and % = +, then evaluate: 8 @ 3 # 4 % 6 2
Answer: 23
After substitution, the expression becomes 8 × 3 - 4 + 6 ÷ 2. Using BODMAS, 8 × 3 = 24 and 6 ÷ 2 = 3, so the result is 24 - 4 + 3 = 23.