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Angle of deviation (δ) by a prism (refractive index = μ and supposing the angle of prism A to be small) can be given by
- δ = (μ − 1)A
- δ = √(μ + 1)A
- δ = sin 4A / 2
- δ = μ − 1 / μ + 1 A
Correct answer: δ = (μ − 1)A
Solution
For a small angle of the prism (A), the angle of deviation (δ) is approximately given by δ = (μ − 1)A, where μ is the refractive index of the prism. This is derived from the prism formula under the small-angle approximation.
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