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A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that its end closer to the pole is 20 cm away from the mirror. The length of the image is:
- 10 cm
- 2.5 cm
- 15 cm
- 5 cm
Correct answer: 5 cm
Solution
The image of the rod is formed by considering the magnification at each end. For the end at 20 cm, magnification is -1/2, and for the end at 30 cm, magnification is -1/3. The difference in image positions gives the length of the image as 5 cm.
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