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A conductor of length 0.4 m is moving with a speed of 7 m/s perpendicular to a magnetic field of intensity 0.9 Wb/m². The induced e.m.f. across the conductor is

1. 1.26 V
2. 2.52 V
3. 5.04 V
4. 25.2 V

Correct answer: 1.26 V

Solution

The induced emf is given by the formula E = B * l * v, where B is the magnetic field, l is the length of the conductor, and v is the velocity. Substituting the values: E = 0.9 * 0.4 * 7 = 1.26 V.

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