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The charge through the coil = area of current-time (I-t) graph. q = 1/2 × 0.1 × 4 = 0.2C. Change in flux (Δϕ) = q × R.

1. Δϕ = 2 Weber
2. Δϕ = 1 Weber
3. Δϕ = 0.5 Weber
4. Δϕ = 3 Weber

Correct answer: Δϕ = 1 Weber

Solution

The charge (q) is calculated as the area under the current-time graph, which is given as 0.2 C. Using the formula Δϕ = q × R, and assuming R = 5 Ω (not explicitly stated but inferred from the calculation), Δϕ = 0.2 × 5 = 1 Weber.

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