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In an inductor of self-inductance L = 2 mH, current changes with time according to relation i = Ie^(-t). At what time emf is zero?

1. 4s
2. 3s
3. 2s
4. 1s

Correct answer: 4s

Solution

The emf across an inductor is given by E = -L(di/dt). Differentiating i = Ie^(-t), we get di/dt = -Ie^(-t). Substituting this into the emf equation, E = L * Ie^(-t). Since e^(-t) is never zero for any finite t, the emf is never zero. The question seems to have an issue.

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