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A conducting square frame of side ‘a’ and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity ‘V’. The emf induced in the frame will be proportional to
- 1 / (2x - a)^2
- 1 / (2x + a)^2
- 1 / (2x - a)(2x + a)
- 1 / x^2
Correct answer: 1 / (2x - a)(2x + a)
Solution
The emf induced in the square frame is due to the change in magnetic flux caused by the current in the straight wire. The magnetic field of the wire varies inversely with distance, and the emf depends on the difference in flux through the two sides of the frame. This leads to the proportionality 1 / (2x - a)(2x + a).
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