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Two coils of inductances 2 mH and 8 mH are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is
- 6 mH
- 4 mH
- 16 mH
- 10 mH
Correct answer: 4 mH
Solution
The mutual inductance (M) between two coils is given by the geometric mean of their individual inductances when the flux linkage is complete: M = √(L1 × L2). Substituting L1 = 2 mH and L2 = 8 mH, we get M = √(2 × 8) = √16 = 4 mH.
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