A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is 4 × 10⁻³ Wb. The self inductance of the solenoid is:

Question

Accepted Answer

4H. The self-inductance (L) of the solenoid is given by the formula L = NΦ/I, where N is the number of turns, Φ is the magnetic flux per turn, and I is the current. Substituting the values: L = (1000 × 4 × 10⁻³) / 4 = 4 H.

A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is 4 × 10⁻³ Wb. The self inductance of the solenoid is:

Solution

Related NEET Physics questions