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A cycle wheel of radius 0.5 m is rotated with constant angular velocity of 10 rad/s in a region of magnetic field of 0.1 T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is

1. zero
2. 0.25 V
3. 0.125 V
4. 0.5 V

Correct answer: 0.125 V

Solution

The EMF generated in a rotating wheel is given by the formula \( \text{EMF} = \frac{1}{2} B \omega R^2 \). Substituting \( B = 0.1 \ \text{T}, \omega = 10 \ \text{rad/s}, R = 0.5 \ \text{m} \), we get \( \text{EMF} = \frac{1}{2} \times 0.1 \times 10 \times (0.5)^2 = 0.125 \ \text{V} \).

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