Exams › NEET › Physics
A magnetic field of 2 × 10⁻² T acts at right angles to a coil of area 100 cm², with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is
- 10 s
- 0.1 s
- 0.01 s
- 1 s
Correct answer: 1 s
Solution
The induced emf is given by Faraday's law: E = -dΦ/dt, where Φ = NBA. Here, N = 50, B = 2 × 10⁻² T, A = 100 cm² = 10⁻² m². So, Φ = 50 × 2 × 10⁻² × 10⁻² = 10⁻² Wb. Given E = 0.1 V, t = Φ/E = (10⁻²)/(0.1) = 1 s.
Related NEET Physics questions
⚔️ Practice NEET Physics free + battle 1v1 →