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A magnetic field of 2 × 10⁻² T acts at right angles to a coil of area 100 cm², with 50 turns. The average e.m.f. induced in the coil is 0.1 V, when it is removed from the field in t sec. The value of t is

  1. 10 s
  2. 0.1 s
  3. 0.01 s
  4. 1 s

Correct answer: 1 s

Solution

The induced emf is given by Faraday's law: E = -dΦ/dt, where Φ = NBA. Here, N = 50, B = 2 × 10⁻² T, A = 100 cm² = 10⁻² m². So, Φ = 50 × 2 × 10⁻² × 10⁻² = 10⁻² Wb. Given E = 0.1 V, t = Φ/E = (10⁻²)/(0.1) = 1 s.

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