A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction 1/(√π) (Wb/m²) in such a way that its axis makes an angle of 60° with B. The magnetic flux linked with the disc is:

Question

Accepted Answer

0.02 Wb. The magnetic flux is given by Φ = B × A × cosθ. Here, B = 1/√π Wb/m², A = πr² = π(0.2)² = 0.04π m², and θ = 60°. Substituting, Φ = (1/√π) × 0.04π × cos60° = 0.02 Wb.

A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction 1/(√π) (Wb/m²) in such a way that its axis makes an angle of 60° with B. The magnetic flux linked with the disc is:

Solution

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