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As a result of change in the magnetic flux linked to the closed loop shown in the Fig, an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is

1. QV
2. 2QV
3. QV/2
4. Zero

Correct answer: QV

Solution

The work done in moving a charge Q through a potential difference V is given by W = QV. This is a direct application of the relationship between work, charge, and potential difference.

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