Exams › NEET › Physics

A coil of resistance 400Ω is placed in a magnetic field. If the magnetic flux Φ (wb) linked with the coil varies with time t (sec) as Φ = 50t² + 4. The current in the coil at t = 2 sec is

1. 0.5 A
2. 0.1 A
3. 2 A
4. 1 A

Correct answer: 0.5 A

Solution

The induced EMF is given by Faraday's law as E = -dΦ/dt. Differentiating Φ = 50t² + 4, we get dΦ/dt = 100t. At t = 2 s, dΦ/dt = 100 × 2 = 200 V. The current is I = E/R = 200/400 = 0.5 A.

Related NEET Physics questions

• Which of the following statement regarding transformer is incorrect?
• Which one of the following statements is true?
• Which statement is incorrect related to induced electric field due to changing magnetic flux?
• A dynamo produces an electric current. It is based on the principle:
• In electromagnetic induction, the induced E.M.F is independent of
• A conductor is moved in a varying magnetic field. Name the law which determines the direction of current induced in the conductor:

⚔️ Practice NEET Physics free + battle 1v1 →