An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m⁻¹. The permeability of the material of the rod is: (μ₀ = 4π×10⁻⁷ T m A⁻¹)

Question

Accepted Answer

2.4π×10⁻⁴ T m A⁻¹. The permeability of the material is given by μ = μ₀(1 + χ), where χ is the susceptibility. Substituting μ₀ = 4π×10⁻⁷ T m A⁻¹ and χ = 599, we get μ = 4π×10⁻⁷ × (1 + 599) = 2.4π×10⁻⁴ T m A⁻¹.

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m⁻¹. The permeability of the material of the rod is: (μ₀ = 4π×10⁻⁷ T m A⁻¹)

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