Exams › NEET › Physics

Velocity of source, vₛ = rω = 0.50 × 20 = 10 m/s. n' = (v / (v + vₛ)) × n. Calculate n' when v = 340 m/s, vₛ = 10 m/s, and n = 385 Hz.

1. 374 Hz
2. 1412 Hz
3. 5000 Hz
4. 720 Hz

Correct answer: 374 Hz

Solution

Using the Doppler effect formula for sound, n' = (v / (v + vₛ)) × n. Substituting the values: n' = (340 / (340 + 10)) × 385 = (340 / 350) × 385 = 374 Hz.

Related NEET Physics questions

• In stationary waves, nodes are the points where there is:
• How does the sound produced by a vibrating object in a medium reach your ear?
• is the distance between consecutive corresponding points of the same phase, such as crests, troughs, compressions, rarefactions or zero crossings and is a characteristic of both travelling waves and standing waves, as well as other spatial wave patterns.
• An echo is simply a........of sound.
• The condition for constructive interference is path difference should be equal to :
• In a stationary wave:

⚔️ Practice NEET Physics free + battle 1v1 →