Exams › NEET › Physics

Let f' be the frequency of sound heard by the cliff. For the reflected wave, cliff acts as a source. Calculate 2f = (v + v₀) / (v - v₀) × f' when v = 330 m/s, v₀ = 10 m/s, and f' = 600 Hz.

1. 103 Hz
2. 1412 Hz
3. 5000 Hz
4. 720 Hz

Correct answer: 1412 Hz

Solution

The formula for the reflected wave frequency is given as 2f = (v + v₀) / (v - v₀) × f'. Substituting the values: v = 330 m/s, v₀ = 10 m/s, and f' = 600 Hz, we get 2f = (330 + 10) / (330 - 10) × 600 = 340 / 320 × 600 = 1.0625 × 600 = 1412.5 Hz ≈ 1412 Hz.

Related NEET Physics questions

• In stationary waves, nodes are the points where there is:
• How does the sound produced by a vibrating object in a medium reach your ear?
• is the distance between consecutive corresponding points of the same phase, such as crests, troughs, compressions, rarefactions or zero crossings and is a characteristic of both travelling waves and standing waves, as well as other spatial wave patterns.
• An echo is simply a........of sound.
• The condition for constructive interference is path difference should be equal to :
• In a stationary wave:

⚔️ Practice NEET Physics free + battle 1v1 →