Exams › NEET › Physics

According to Doppler's effect, apparent frequency n' = (v + v₀) / (v + vₛ) × f₀. Calculate the apparent frequency when v = 343 m/s, v₀ = 10 m/s, vₛ = 5 m/s, and f₀ = 1392 Hz.

1. 103 Hz
2. 1412 Hz
3. 5000 Hz
4. 720 Hz

Correct answer: 1412 Hz

Solution

Using the Doppler effect formula, n' = (v + v₀) / (v + vₛ) × f₀, substitute the given values: n' = (343 + 10) / (343 + 5) × 1392 = 353 / 348 × 1392 ≈ 1412 Hz. Thus, the apparent frequency is 1412 Hz.

Related NEET Physics questions

• In stationary waves, nodes are the points where there is:
• How does the sound produced by a vibrating object in a medium reach your ear?
• is the distance between consecutive corresponding points of the same phase, such as crests, troughs, compressions, rarefactions or zero crossings and is a characteristic of both travelling waves and standing waves, as well as other spatial wave patterns.
• An echo is simply a........of sound.
• The condition for constructive interference is path difference should be equal to :
• In a stationary wave:

⚔️ Practice NEET Physics free + battle 1v1 →