StreakPeaked· Practice

ExamsNEETPhysics

We know that the length of pipe closed at one end and for first overtone (l1) = 3λ / 4 and length of the open pipe for third overtone (l2) = 4λ / 2 = 2λ. Therefore, the ratio of lengths l1 / l2 = 3λ / 4 : 2λ = 3 : 8.

  1. l1 / l2 = 3λ / 4 : 2λ = 3 : 8
  2. Length of pipe closed at one end for first overtone (l1) = 3λ / 4
  3. Length of open pipe for third overtone (l2) = 4λ / 2 = 2λ
  4. Ratio of lengths l1 / l2 = 3 : 8

Correct answer: l1 / l2 = 3λ / 4 : 2λ = 3 : 8

Solution

The question asks for the ratio of lengths l1/l2, which is correctly calculated as 3:8 in option A. The other options are intermediate steps or restatements, but A directly answers the question.

Related NEET Physics questions

⚔️ Practice NEET Physics free + battle 1v1 →