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In a stretched string all multiples of frequencies can be obtained i.e., if fundamental frequency is n then higher frequencies will be 2n, 3n, 4n ...

1. n = 1 / 2√(T/m)
2. n = c / l or n / l = constant, K
3. n1l1 = K, n2l2 = K, n3l3 = K
4. Also, l = l1 + l2 + l3

Correct answer: n = 1 / 2√(T/m)

Solution

The fundamental frequency of a stretched string is given by the formula n = (1/2L)√(T/μ), where T is the tension and μ is the linear mass density. This matches option A.

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