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Resonant frequencies for a string fixed at both ends will be fₙ = nv/2L where n = 1, 2, 3.... The difference between two consecutive resonant frequencies is Δfₙ = fₙ₊₁ - fₙ = (n+1)v/2L - nv/2L = v/2L.

1. fₙ = nv/2L
2. n = 1, 2, 3...
3. Δfₙ = fₙ₊₁ - fₙ = v/2L
4. Difference between consecutive frequencies = v/2L

Correct answer: Δfₙ = fₙ₊₁ - fₙ = v/2L

Solution

The difference between two consecutive resonant frequencies is derived as Δfₙ = fₙ₊₁ - fₙ = v/2L, which matches option C.

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