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A string is stretched between two fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. The lowest resonant frequency for this string is

1. 205 Hz
2. 105 Hz
3. 155 Hz
4. 105 Hz

Correct answer: 105 Hz

Solution

The difference between consecutive resonant frequencies is the fundamental frequency. Here, 420 Hz - 315 Hz = 105 Hz. Thus, the lowest resonant frequency is 105 Hz.

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