Exams › NEET › Physics

Two vibrating tuning forks produce progressive waves given by y₁ = 4 sin 500 πt and y₂ = 2 sin 506 πt. Number of beats produced per minute is

1. 360
2. 180
3. 60
4. 3

Correct answer: 180

Solution

The beat frequency is the difference in frequencies of the two waves. Here, f₁ = 250 Hz and f₂ = 253 Hz (from ω = 2πf). The beat frequency is |f₂ - f₁| = 3 Hz. In one minute, the number of beats is 3 × 60 = 180.

Related NEET Physics questions

• In stationary waves, nodes are the points where there is:
• How does the sound produced by a vibrating object in a medium reach your ear?
• is the distance between consecutive corresponding points of the same phase, such as crests, troughs, compressions, rarefactions or zero crossings and is a characteristic of both travelling waves and standing waves, as well as other spatial wave patterns.
• An echo is simply a........of sound.
• The condition for constructive interference is path difference should be equal to :
• In a stationary wave:

⚔️ Practice NEET Physics free + battle 1v1 →