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Two sound waves with wavelengths 5.0 m and 5.5 m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second

1. 0
2. 6
3. 6
4. 12

Correct answer: 6

Solution

The beat frequency is given by the difference in frequencies of the two waves. Using the formula frequency = velocity/wavelength, the frequencies are 330/5 = 66 Hz and 330/5.5 = 60 Hz. The beat frequency is |66 - 60| = 6 Hz.

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