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A cylindrical resonance tube open at both ends has a fundamental frequency, 'f' in air. If half of the length is dipped vertically in water, the fundamental frequency of the air column will be

1. 2f
2. 3f/2
3. f
4. f/2

Correct answer: 2f

Solution

When the tube is open at both ends, the fundamental frequency corresponds to a wavelength twice the length of the tube. If half the tube is submerged in water, it effectively becomes a tube closed at one end, where the fundamental frequency corresponds to a wavelength four times the length of the air column. This doubles the frequency, making it 2f.

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