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Two sound waves having a phase difference of 60° have path difference of

1. 2λ
2. λ/2
3. λ/3
4. λ/6

Correct answer: λ/3

Solution

The phase difference (Δϕ) and path difference (Δx) are related by the formula Δϕ = (2π/λ) * Δx. For a phase difference of 60° (π/3 radians), solving for Δx gives Δx = (λ/2π) * (π/3) = λ/3.

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