Exams › NEET › Physics

The length of the wire between two ends of a sonometer is 100 cm. What should be the positions of two bridges below the wire so that the three segments of the wire have their fundamental frequencies in the ratio of 1 : 3 : 5?

1. 1500/23 cm, 2000/23 cm
2. 1500/23 cm, 500/23 cm
3. 1500/23 cm, 300/23 cm
4. 300/23 cm, 1500/23 cm

Correct answer: 1500/23 cm, 2000/23 cm

Solution

The wire is divided into three segments with lengths proportional to the inverse of the fundamental frequency ratio (1:3:5). The total length is 100 cm, so the segments are 50/23 cm, 150/23 cm, and 250/23 cm. The positions of the bridges are at 1500/23 cm and 2000/23 cm from one end.

Related NEET Physics questions

• In stationary waves, nodes are the points where there is:
• How does the sound produced by a vibrating object in a medium reach your ear?
• is the distance between consecutive corresponding points of the same phase, such as crests, troughs, compressions, rarefactions or zero crossings and is a characteristic of both travelling waves and standing waves, as well as other spatial wave patterns.
• An echo is simply a........of sound.
• The condition for constructive interference is path difference should be equal to :
• In a stationary wave:

⚔️ Practice NEET Physics free + battle 1v1 →