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The number of possible natural oscillation of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (velocity of sound = 340 ms⁻¹)

1. 4
2. 5
3. 6
4. 7

Correct answer: 5

Solution

For a pipe closed at one end, the natural frequencies are given by f = (2n-1)v/4L, where n = 1, 2, 3,..., v = 340 m/s, and L = 0.85 m. Solving for n such that f < 1250 Hz, we find n = 5. Thus, there are 5 possible natural oscillations.

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