Exams › NEET › Physics
The two nearest harmonics of a tube closed at one end and open at the other are 220 Hz and 260 Hz. What is the fundamental frequency of the system?
- 20 Hz
- 30 Hz
- 40 Hz
- 10 Hz
Correct answer: 40 Hz
Solution
For a tube closed at one end, the harmonics are odd multiples of the fundamental frequency (f). The difference between consecutive harmonics is twice the fundamental frequency. Here, 260 Hz - 220 Hz = 40 Hz, so the fundamental frequency is 40 Hz.
Related NEET Physics questions
⚔️ Practice NEET Physics free + battle 1v1 →