The phase difference between two waves, represented by y₁ = 10⁻⁶ sin{100 t + (x/50) + 0.5} m and y₂ = 10⁻⁶ cos{100 t + (x/50)} m, where x is expressed in meters and t is expressed in seconds, is approximately:

Question

Accepted Answer

0.5 radians. The phase difference between the sine and cosine functions is π/2 radians (or 0.5 radians). This is evident because the cosine function can be expressed as a sine function with a phase shift of π/2.

The phase difference between two waves, represented by y₁ = 10⁻⁶ sin{100 t + (x/50) + 0.5} m and y₂ = 10⁻⁶ cos{100 t + (x/50)} m, where x is expressed in meters and t is expressed in seconds, is approximately:

Solution

Related NEET Physics questions