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The equation for a transverse wave travelling along the positive x-axis with amplitude 0.2 m, velocity v = 360 m/s and wavelength λ = 60 m can be written as:

1. y = 0.2 sin [2π (6t − x/60)]
2. y = 0.2 sin [2π (6t + x/60)]
3. y = 0.2 sin [π (6t − x/60)]
4. y = 0.2 sin [π (6t + x/60)]

Correct answer: y = 0.2 sin [2π (6t − x/60)]

Solution

The general equation for a transverse wave traveling along the positive x-axis is y = A sin(2π(ft - x/λ)). Here, A = 0.2 m, λ = 60 m, and v = 360 m/s. Using v = fλ, we find f = v/λ = 360/60 = 6 Hz. Substituting these values, the equation becomes y = 0.2 sin[2π(6t - x/60)].

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