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Two waves are represented by the equations y₁ = sin (ωt + kx + 0.57) m and y₂ = cos (ωt + kx) m, where x is in meter and t in sec. The phase difference between them is

1. 1.0 radian
2. 1.25 radian
3. 1.57 radian
4. 0.57 radian

Correct answer: 1.57 radian

Solution

The given equations can be rewritten in terms of sine for comparison. The second wave, y₂ = cos(ωt + kx), can be expressed as y₂ = sin(ωt + kx + π/2). Comparing the phases, the phase difference is π/2 - 0.57 ≈ 1.57 radians.

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