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Time period of simple pendulum is given by T = 2π√(l/g), where l is effective length. Initially, centre of gravity is at the centre of sphere. When water leaks the centre of gravity goes down until it is half filled; then it begins to go up and finally it again goes at the centre. That is effective length first increases and then decreases. As T ∝ √l, so time period first increases and then decreases.

1. Time period of simple pendulum
2. Acceleration due to gravity
3. Effective length of pendulum
4. None of the above

Correct answer: Time period of simple pendulum

Solution

The question describes the variation of the time period of a simple pendulum as the effective length changes due to the shifting center of gravity. Since the time period is directly proportional to the square root of the effective length, the correct answer is 'Time period of simple pendulum'.

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