Exams › NEET › Physics

Speed v = √ω√(a² - x²), x = a/2.

1. v = √ω√a² - x²
2. v = 2π√a²/4
3. v = 3a²/4
4. v = 2π√3√a√5/4

Correct answer: v = √ω√a² - x²

Solution

The given equation for speed is v = √ω√(a² - x²). Substituting x = a/2 into the equation, we get v = √ω√(a² - (a/2)²) = √ω√(a² - a²/4) = √ω√(3a²/4) = √ω(√3a/2). The correct option is A.

Related NEET Physics questions

• One oscillation completed by a vibrating body in one second is known as:
• A body executes simple harmonic motion. The potential energy (P.E.), the kinetic energy (K.E.) and total energy (T.E.) are measured as a function of time t. Which of the following statements is true. Assume that the particle started at \( t=0 \) at its mean position
• The amplitude of a particle executing SHM about O is 10 cm. Then: This question has multiple correct options
• The displacement (in \( \mathrm{m} \) ) of a particle of mass 100 gram from its equilibrium position is given by \( \boldsymbol{y}=\mathbf{0 . 0 1} \sin 2 \pi(t+ \) 0.4). Select the correct option(s): This question has multiple correct options
• Three simple harmonic motions in the same direction having the same amplitude \( A \) and same period are superposed. If each differs in phase from the next by \( 45^{0}, \) then
• A particle executes \( \boldsymbol{S} \boldsymbol{H} \boldsymbol{M} \) of amplitude \( 25 c m \) and time period \( 3 s \) What is the minimum time required for the particle to move between two points \( 12.5 \mathrm{cm} \) on either side of the mean position?

⚔️ Practice NEET Physics free + battle 1v1 →