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Mass gets detached at the upper extreme position when pan returns to its mean position. At that point, R = mg - mω²a = 0 i.e. g = ω²a.

1. a = g/ω² = mg/k
2. a = 2×10/200
3. a = 1/10m = 10cm
4. Displacement from the mean position y = a sin(2π/T)t

Correct answer: a = g/ω² = mg/k

Solution

The condition for detachment is when the normal force becomes zero, which occurs at the upper extreme position. Using the equation g = ω²a, we solve for a as a = g/ω². This matches option A.

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