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P.E. = 1/2 mω²x² and K.E. = 1/2 mω²(A² - x²).

1. T/V = a² - x²/x²
2. T/V = x²/a²
3. T/V = a²/x²
4. T/V = x²/(a² - x²)

Correct answer: T/V = x²/(a² - x²)

Solution

The ratio of potential energy (P.E.) to kinetic energy (K.E.) is given by T/V = (1/2 mω²x²) / (1/2 mω²(A² - x²)) = x² / (A² - x²).

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