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Force constant k = 2 × 10⁶ N/m, Amplitude (x) = 0.01 m. Calculate the potential energy.

1. 100 J
2. 200 J
3. 50 J
4. 25 J

Correct answer: 50 J

Solution

The potential energy in a spring is given by U = (1/2)kx². Substituting k = 2 × 10⁶ N/m and x = 0.01 m, we get U = (1/2)(2 × 10⁶)(0.01)² = 100 J.

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