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Total energy of particle executing S.H.M. of amplitude (A).

1. 1/2 mω²A²
2. 1/2 mω²A
3. 1/2 mω²A² when x = A/2
4. 1/2 mω²A² when x = A

Correct answer: 1/2 mω²A²

Solution

The total energy of a particle in simple harmonic motion is given by the sum of its kinetic and potential energies, which is constant and equal to (1/2) mω²A², where A is the amplitude.

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