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If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0 m/s² at any time, the angular frequency of the oscillator is equal to

1. 10 rad/s
2. 0.1 rad/s
3. 100 rad/s
4. 1 rad/s

Correct answer: 10 rad/s

Solution

In SHM, acceleration is given by a = -ω²x. Substituting a = 2.0 m/s² and x = 0.02 m, we get ω² = a/x = 2.0/0.02 = 100. Thus, ω = √100 = 10 rad/s.

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