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A simple harmonic oscillator has an amplitude A and time period T. The time required by it to travel from x = A to x = A/2 is

1. T/6
2. T/4
3. T/3
4. T/2

Correct answer: T/6

Solution

In SHM, the displacement x = A cos(ωt). For x = A/2, cos(ωt) = 1/2, which gives ωt = π/3. Since ω = 2π/T, the time t = (T/6).

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